A) \[{{I}_{0}}\]
B) \[{{I}_{0}}/2\]
C) \[{{I}_{0}}/4\]
D) \[{{I}_{0}}/8\]
Correct Answer: C
Solution :
[c] According to Malus' law \[I={{I}_{0}}{{\cos }^{2}}\theta ={{I}_{0}}({{\cos }^{2}}{{60}^{o}})={{I}_{0}}\times {{\left( \frac{1}{2} \right)}^{2}}=\frac{{{I}_{0}}}{4}.\]
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