A) I
B) \[I/2\]
C) \[I/\sqrt{2}\]
D) zero
Correct Answer: B
Solution :
[b] \[I'=I{{\cos }^{2}}\theta =I{{\cos }^{2}}({{45}^{o}})=I{{\left( \frac{I}{\sqrt{2}} \right)}^{2}}=\frac{I}{2}\]
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