A) the slit is approximately 0.005 cm wide
B) the slit is approximately 0.05 cm wide
C) \[a/\lambda \], is approximately 7.5 (a is the slit width)
D) \[a/\lambda \]is approximately 750
Correct Answer: A
Solution :
[a] \[\sin {{\theta }_{2}}=\frac{2\lambda }{d}\] or \[{{\theta }_{2}}={{\sin }^{-1}}\left( \frac{2\lambda }{d} \right)\] Given \[y=D(2\,{{\theta }_{2}})=8\times {{10}^{-2}}\] or \[1.5\times 2\times {{\sin }^{-1}}\left( \frac{2\lambda }{d} \right)=8\times {{10}^{-2}}\] \[\Rightarrow d\simeq 0.005cm\]
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