JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    The angle of polarisation for any medium is \[60{}^\circ \]The critical angle for this is

    A) \[{{\sin }^{-1}}\frac{1}{\sqrt{3}}\]

    B) \[{{\cos }^{-1}}\sqrt{3}\]

    C) \[{{\sin }^{-1}}\sqrt{3}\]

    D) \[{{\tan }^{-1}}\sqrt{3}\]

    Correct Answer: A

    Solution :

    [a] \[\mu =\tan {{i}_{p}}=\tan {{60}^{o}}=\sqrt{3}\] \[\sin {{i}_{C}}=\frac{1}{\mu }=\frac{1}{\sqrt{3}}\Rightarrow {{i}_{C}}={{\sin }^{-1}}\frac{1}{\sqrt{3}}\]


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