A) \[~3300\,\overset{o}{\mathop{A}}\,\]
B) \[4400\,\overset{o}{\mathop{A}}\,\]
C) \[5500\overset{o}{\mathop{\,A}}\,\]
D) \[6600\,\overset{o}{\mathop{A}}\,\]
Correct Answer: B
Solution :
[b] In a single slit experiment, For diffraction maxima, \[a\,\sin \theta =(2n+1)\frac{\lambda }{2}\] and for diffraction minima, \[a\,\sin \theta =n\lambda \] According to question, \[(2\times 1+1)\frac{\lambda }{2}=1\times 6600\] \[(\because \,\,\,{{\lambda }_{R}}=6600\overset{o}{\mathop{A}}\,)\] \[\lambda =\frac{6600\times 2}{3}=4400\overset{o}{\mathop{A}}\,\]
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