A) \[1:30\]
B) \[1:49\]
C) \[1:51\]
D) \[1:73\]
Correct Answer: B
Solution :
[b] As shown in the figure, the interference will be between \[0.25I={{I}_{1}}\] and \[0.14I={{I}_{2}}\] \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{\left( \sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}} \right)}^{2}}}{{{\left( \sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}} \right)}^{2}}}=\frac{{{[\sqrt{0.25I}+\sqrt{0.14I}]}^{2}}}{{{[\sqrt{0.25I}-\sqrt{0.14I}]}^{2}}}=\frac{49}{1}\]
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