JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Self Evaluation Test - Wave Optics

  • question_answer
    (distance between slit and screen D = 12cm and distance between slits d = 5cm.) then the wavelength of the radiation used can be-

    A) 3/4 cm             

    B) 4 cm, 5cm

    C) 2/3 cm, 2/5 cm    

    D) 4/3 cm, 5/3 cm

    Correct Answer: C

    Solution :

    [c] Path difference \[\sqrt{{{D}^{2}}+{{d}^{2}}}-D=1cm\]. Also, \[[\sqrt{{{D}^{2}}+{{d}^{2}}}-D]=(2n-1)\frac{\lambda }{2}\Rightarrow \lambda =\frac{2(1)}{2n-1}\] For n= 1, 2, 3.................... \[\lambda =2cm,\,\frac{2}{3}cm,\,\frac{2}{5}cm,\,\]................


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