A) toward A
B) toward B
C) by \[t(\mu -1)\frac{\beta }{\lambda }\]
D) by \[\mu t\frac{\beta }{\lambda }\]
Correct Answer: A
Solution :
[a] For central maximum at P, \[\frac{xd}{D}=t(\mu -1)\] or \[x=t(\mu -1)\frac{D}{d}\] Now, \[\beta =\frac{D\lambda }{d}\] \[\therefore \,\,\,\frac{D}{d}=\frac{\beta }{\lambda }\] Hence, \[x=t(\mu -1)\frac{\beta }{\lambda }\]
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