A) 1.0 radian
B) 1.25 radian
C) 1.57 radian
D) 0.57 radian
Correct Answer: A
Solution :
[a] Here, \[{{y}_{1}}=a\,\sin \,(\omega t+kx+0.57)\] and \[{{y}_{2}}=a\,\cos \,(\omega t+kx)\] \[=a\,\sin \left[ \frac{\pi }{2}+(\omega t+kx) \right]\] Phase difference, \[\Delta \phi ={{\phi }_{2}}={{\phi }_{1}}\] \[=\frac{\pi }{2}-0.57\] \[=\frac{3.14}{2}-0.57=1.57-0.57=1\,radian\]You need to login to perform this action.
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