A) \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}-5t)}\]
B) \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}}\]
C) \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x+5t)}^{2}}}\]
D) \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}+5t)}\]
Correct Answer: B
Solution :
[b] \[y(x,t)=f(x-vt)\] \[y=(x,0)=\frac{4\times {{10}^{-3}}}{8-{{x}^{2}}}\] For a travelling wave in the x-direction \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}}\]You need to login to perform this action.
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