A) \[Y=(2mm)\sin (5t-40x)\]
B) \[Y=(4mm)\sin (40x-5t)\]
C) \[Y=-(2mm)\sin (5t-40x)\]
D) \[Y=(2mm)\sin (5t-10x)\]
Correct Answer: C
Solution :
[c] \[{{v}_{1}}=\sqrt{\frac{T}{\mu }};\,\,\,{{v}_{2}}=\sqrt{\frac{T}{4\mu }}\]You need to login to perform this action.
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