A) 4.0 N
B) 12.5 N
C) 0.5 N
D) 6.25 N
Correct Answer: D
Solution :
[d] \[T=\mu \,{{v}^{2}}=\mu \frac{{{\omega }^{2}}}{{{k}^{2}}}=0.04\frac{{{(2\pi /0.004)}^{2}}}{{{(2\pi /0.50)}^{2}}}\] 6.25 NYou need to login to perform this action.
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