A) \[n=3,\,{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]
B) \[n=3,\,{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]
C) \[n=5,\,{{f}_{2}}=\frac{3}{4}{{f}_{1}}\]
D) \[n=5,\,{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]
Correct Answer: D
Solution :
[d] \[\lambda =\ell \] \[\therefore \,\,\,\,{{f}_{1}}=\frac{v}{\lambda }=\frac{v}{\ell }\] ?. (i) \[\lambda =\frac{4\ell }{n}\] \[\therefore \,\,\,{{f}_{2}}=\frac{v}{\lambda }=\frac{nv}{4\ell }\] ?. (ii) Here n is a odd number. From (i) and (ii) \[{{f}_{2}}=\frac{n}{4}{{f}_{1}}\] For first resonance, \[n=5,\,{{f}_{2}}=\frac{5}{4}{{f}_{1}}\]You need to login to perform this action.
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