A) 18.75 J
B) 25.00 J
C) 6.25 J
D) 12.50 J
Correct Answer: A
Solution :
[a] \[{{\operatorname{W}}_{1}}=\frac{1}{2}\times 5\times {{10}^{3}}{{\left( 0.05 \right)}^{2}}\] \[\Rightarrow {{W}_{2}}=\frac{1}{2}\times 5\times 1{{0}^{3}}{{\left( 0.10 \right)}^{2}}\] \[\therefore \Delta W=\frac{1}{2}\times 5\times 1{{0}^{3}}\times 0.15\times 0.05 =18.75J.\]
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