A) 4.05 m/s
B) 4.00 m/s
C) 3.00 m/s
D) 3.50 m/s
Correct Answer: A
Solution :
[a] \[y=10-\sqrt{{{10}^{2}}-{{4}^{2}}}=0.84m\] Thus\[\frac{1}{2}m{{v}^{2}}=mgy\] Or \[v=\sqrt{2gy}=\sqrt{2\times 9.8\times 0.84}\] \[=4.05\text{ }m/s.\]You need to login to perform this action.
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