Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति
JEE Main & Advanced
Physics
Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति
Question Bank
Self Evaluation Test - Work, Energy and Power
question_answer
A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from \[x=0\] to \[x=6\] m is
A)18.0 J
B)13.5 J
C)9.0 J
D)4.5 J
Correct Answer:
B
Solution :
[b] Work done = area under F-x graph = area of trapezium \[\operatorname{OABC} =\frac{1}{2}\left( 3 + 6 \right)\left( 3 \right)\] \[=13.5J\]