JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Self Evaluation Test - Work, Energy and Power

  • question_answer
    The work done by a force\[\vec{F}=\left( -6{{x}^{3}}\hat{i} \right)N,\]in displacing a particle from \[x=4\text{ }m\text{ }to\text{ }x=-2\]m is

    A) \[360J\]

    B) \[240J\]

    C) \[-240J\]

    D) \[-360J\]

    Correct Answer: A

    Solution :

    [a] \[\operatorname{w}=\int\limits_{{{x}_{1}}}^{{{x}_{2}}}{Fdx}=\int\limits_{4}^{-2}{-6{{x}^{3}}dx}\] \[=-6{{\left| \frac{{{x}^{4}}}{4} \right|}^{-2}}_{4}=\frac{-6}{4}\left[ {{\left( -2 \right)}^{4}}-{{\left( 4 \right)}^{2}} \right]=360J.\]


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