A) 60%
B) 40%
C) 20%
D) 30%
Correct Answer: D
Solution :
[d] \[{{P}_{out}}=\frac{mgh}{t}=\frac{9000\times 10\times 10}{5\times 60}=3600W\] \[{{P}_{in}}=10\times {{10}^{3}}\operatorname{w}.\] \[\therefore \eta =\frac{{{P}_{out}}}{{{P}_{in}}}\times 100=\frac{3000}{10\times {{10}^{3}}}\times 100=30%\]You need to login to perform this action.
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