A) \[10\text{ }J,\text{ }20\text{ }J\]
B) \[10\,J,\text{ }10\,J\]
C) \[15\text{ }J,\text{ }8\text{ }J\]
D) \[8\,J,16\,J\]
Correct Answer: B
Solution :
[b] Total energy at the time of projection \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\times 0.1{{\left( 20 \right)}^{2}}=20\operatorname{J}\] Half way up, P.E. becomes half the P.E. at the top i.e.\[P.E.=\frac{20}{2}=10\operatorname{J}\] \[\therefore K.E. =20-10=10J\]
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