A) \[\sqrt{t}\]
B) constant
C) \[t\]
D) \[\frac{1}{\sqrt{t}}\]
Correct Answer: D
Solution :
[d] Given, \[\frac{\operatorname{dk}}{\operatorname{dt}}= constant\] \[\Rightarrow \,\,k\propto t\Rightarrow v\propto \sqrt{t}\] \[\operatorname{Also}, P=Fv=\frac{dk}{dt}= constant\] \[\Rightarrow F\propto \frac{1}{v}\Rightarrow F\propto \frac{1}{\sqrt{t}}\]
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