A) 9 : 1
B) 2 : 9
C) 1 : 9
D) 9 : 2
Correct Answer: C
Solution :
[c] Let E be the total energy then \[\frac{P.E}{K.E}=\frac{mgh}{E-mgh}=\frac{2}{3}\Rightarrow E=\frac{5}{2}mgh\] When velocity is double then inital energy becomes 4E. So, \[\frac{mgh}{4E-mgh}=NL=\frac{mgh}{10mgh-mgh}\] On solving we get\[\frac{P.E}{K.E}=\frac{1}{9}\].You need to login to perform this action.
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