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JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Self Evaluation Test - Work, Energy and Power

  • question_answer
    The potential energy of a conservative system is given by\[\operatorname{U} = a{{y}^{2}}-by\], where y represents the position of the particle and a as well as b are constants. What is the force acting on the system?

    A) \[-ay\]

    B) \[-by\]

    C) \[2ay-b\]

    D) \[\operatorname{b}-2ay\]

    Correct Answer: D

    Solution :

    [d] \[\operatorname{F}=-\frac{dU}{dy}=b-2ay\]


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