A) 100J
B) zero
C) 1000J
D) 200J
Correct Answer: A
Solution :
[a] Work done against gravity \[=mg\text{ }sin\theta \times d\] \[=2\times 10\times 10=200J \left( d\,sin\theta =10 \right)\] Actual work done = 300 J Work done against friction \[= 300 - 200 = 100 J\]
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