A) 1.7 m/s
B) 17 m/s
C) 27 m/s
D) 34 m/s
Correct Answer: B
Solution :
[b] \[{{W}_{gravity}}+{{W}_{F}}=\Delta K\] \[-10\times g\left( 10-10cos60{}^\circ \right)+200\times 10sin60{}^\circ \] \[=\frac{1}{2}\times 10\times {{v}_{f}}^{2}-0~\therefore {{v}_{f}}=17m/s\]
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