A) 25
B) 30
C) 50
D) 100
Correct Answer: A
Solution :
[a] \[{{\operatorname{U}}_{1}}=mg{{h}_{1}}\,and\,{{U}_{2}}=mg{{h}_{2}}\] \[% energy lost = \frac{{{U}_{1}}-{{U}_{2}}}{{{U}_{1}}}\times 100\] \[=\frac{mg{{h}_{1}}-mg{{h}_{2}}}{mg{{h}_{1}}}\times 100=\left( \frac{{{h}_{1}}-{{h}_{2}}}{{{h}_{1}}} \right)\times 100\] \[=\frac{2-1.5}{2}\times 100=25%\]
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