JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Self Evaluation Test - Work, Energy and Power

  • question_answer
    A running man has half the kinetic energy of that of a boy of half of his mass. The man speeds up by 1m/s so as to have same K.E. as that of the boy. The original speed of the man will be

    A) \[\sqrt{2}m/s\]

    B) \[\left( \sqrt{2}-1 \right)m/s\]

    C)  \[\frac{1}{\left( \sqrt{2}-1 \right)}m/s\]

    D)

    Correct Answer: C

    Solution :

    [c] Let\[m=mass\text{ }of\text{ }boy\], \[M=mass\text{ }of\text{ }man\]\[v=velocity\text{ }of\text{ }boy\], \[V=velocity\text{ }of\text{ }man\] \[\frac{1}{2}M{{V}^{2}}=\frac{1}{2}\left[ \frac{1}{2}m{{v}^{2}} \right]\]                  ?(i) \[\frac{1}{2}M{{\left( V+1 \right)}^{2}}=1\left[ \frac{1}{2}m{{v}^{2}} \right]\] ?(ii) \[\operatorname{Putting} m = \frac{M}{2} and solving V= \frac{1}{\sqrt{2}-1}\]


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