A) Proton
B) Electron
C) Deutron
D) a-particles
Correct Answer: B
Solution :
[b] \[\operatorname{E}=\frac{{{P}^{2}}}{2m}\therefore E\propto \frac{1}{m}\] [If P= constant] i.e. the lightest particle will possess maximum kinetic energy and in the givenYou need to login to perform this action.
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