question_answer

A force F acting on an object varies with distance x as shown here. The force is in N and x in m. The work done by the force in moving the object from \[x=0\] to \[x=6\] m is

A) 18.0 J

B) 13.5 J

C) 9.0 J

D) 4.5 J

Correct Answer: B

Solution :

[b] Work done = area under F-x graph = area of trapezium \[\operatorname{OABC} =\frac{1}{2}\left( 3 + 6 \right)\left( 3 \right)\] \[=13.5J\]