JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Self Evaluation Test - Work, Energy and Power

  • question_answer
    A particle describe a horizontal circle of radius 0.5 m with uniform speed. The centripetal force acting is 10 N. The work done in describing a semicircle is

    A) zero

    B) 5J   

    C) \[5\pi J\]

    D) \[10\,\pi J\]

    Correct Answer: A

    Solution :

    [a] \[\operatorname{W}=F\,s\,cos90{}^\circ =zero\]


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