A) 1:2
B) 1:1
C) 2:1
D) 1:3
Correct Answer: C
Solution :
[c] \[\operatorname{Power}=\frac{work done}{time}\] Therefore power of A, \[{{\operatorname{P}}_{A}}=\frac{mgh}{{{t}_{A}}}\] and power of B,\[{{\operatorname{P}}_{\operatorname{B}}}=\frac{mgh}{{{t}_{\operatorname{B}}}}\] \[\therefore \frac{{{P}_{A}}}{{{P}_{B}}}=\frac{{{t}_{B}}}{{{t}_{A}}}=\frac{4}{2}=2:1\]
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