A) 550 J
B) 650 J
C) 450 J
D) 250 J
Correct Answer: B
Solution :
[b] Using relative velocity, time of flight before collision will be \[t=\frac{20}{20}=15\] By COM at the time of collision \[3\times 10-1\times 10=4\times v\] \[2\times 10=4\times v;\,\,5=v\] \[v=5m/s\] For 1-D motion \[{{\operatorname{v}}^{2}}={{u}^{2}}+2as={{5}^{2}}+2\times 10\times 15=25+300=325\]\[K=650\text{ }J\]You need to login to perform this action.
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