A) 1 watt
B) 2 watt
C) 3 watt
D) 4 watt
Correct Answer: D
Solution :
[d] \[\operatorname{m}= 1 kg, a = 1 m/{{s}^{2}}\] \[\mu =0.1\] \[f=\mu \,\,mg=0.1\times 1\times 10=1N\] \[{{\operatorname{F}}_{ext}}=ma+f~~~{{F}_{ext}}=1+l=2N\] \[\operatorname{v}=u +at=0+1\times 2=2m/sec.\] \[\therefore ~~P={{F}_{ext}}v=2\times 2=4watt.\]You need to login to perform this action.
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