A) 8
B) 6
C) 9
D) 11
Correct Answer: A
Solution :
[a] Let m be the mass of the beads. By energy conservation \[\operatorname{mgh} =\frac{1}{2} m{{v}^{2}}_{1}+\frac{1}{2}m{{v}^{2}}_{2}\] ....(i) \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{4}{3}\] ?(ii) \[{{v}_{1}}=\frac{4\sqrt{2}}{5},{{v}_{2}}=\frac{3\sqrt{2}}{5}.,\] \[\operatorname{K}.E.=\frac{1}{2}\times 100\times {{10}^{-3}}\times \frac{16\times 2}{25}=64\times {{10}^{-3}}J\] x=8.
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