A) 0.75kg
B) 1.0kg
C) 1.2kg
D) None of these
Correct Answer: D
Solution :
[d] For the object of mass 2.0 kg. \[\frac{\Delta \operatorname{k}}{\operatorname{k}}=\frac{k-k/4}{k}=\frac{3}{4}\] Kinetic energy transferred \[\frac{\Delta \operatorname{k}}{\operatorname{k}}=\frac{4{{m}_{1}}{{m}_{2}}}{{{\left( {{\operatorname{m}}_{1}}+{{m}_{2}} \right)}^{2}}}\] Here, \[{{\operatorname{m}}_{1}} = 2.0 kg, {{m}_{2}}= M\] \[\therefore \frac{3}{4}=\frac{4\times 2\operatorname{M}}{{{\left( 2+\operatorname{M} \right)}^{2}}}\Rightarrow \operatorname{M}=\frac{2}{3}kg\,\,or\,\,6kg\]
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