A) \[\frac{mghv}{s}\]
B) \[\frac{mghs}{v}\]
C) \[Mghvs\]
D) zero
Correct Answer: A
Solution :
[a] Extra power, \[\operatorname{P} = mg sin \theta \times v\] \[=Mg\times \frac{h}{s}\times v=\frac{Mghv}{s}.\]
You need to login to perform this action.
You will be redirected in
3 sec
