JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Self Evaluation Test - Work, Energy and Power

  • question_answer
    A uniform rope of linear mass density 'k and length (. is coiled on a smooth horizontal surface. One end is pulled up with constant velocity v. Then the average power applied by the external agent in pulling the entire rope just off the horizontal surface is    

    A) \[\frac{1}{2}\lambda \ell {{v}^{2}}+\frac{\lambda {{\ell }^{2}}g}{2}\]

    B)        \[\lambda \ell gv\]

    C) \[\frac{1}{2}\lambda {{v}^{3}}+\frac{\lambda \ell vg}{2}\] 

    D)        \[\lambda \ell vg+\frac{1}{2}\lambda {{v}^{3}}\]

    Correct Answer: C

    Solution :

    [c] Initial\[KE.=0\], Initial \[P.E.=0\] When the rope is just pulled off the table, final \[\operatorname{K}.E =\frac{1}{2}(\lambda \ell ){{v}^{2}}, final P.E. = (\lambda \ell )g\ell /2\] time taken \[=t=\ell /v\] \[\operatorname{Average} power =\frac{net change in energy}{time}\] \[=\frac{\frac{1}{2}\lambda \ell {{v}^{2}}+\lambda \ell g\ell /2}{\ell /v}=\frac{1}{2}\lambda {{v}^{3}}+\frac{\lambda \ell vg}{2}\]


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