A) \[(x+y):1\]
B) \[(x-y):(x+y)\]
C) \[1:({{x}^{2}}-{{y}^{2}})\]
D) \[({{x}^{2}}+{{y}^{2}}):({{x}^{2}}-{{y}^{2}})\]
E) None of these
Correct Answer: C
Solution :
\[\frac{\cancel{x}+\cancel{y}}{\cancel{x}-\cancel{y}}\times \frac{{{\cancel{x}}^{2}}+y}{{{\left( \cancel{x}+\cancel{y} \right)}^{2}}}\times \frac{\frac{{{\cancel{x}}^{2}}-{{\cancel{y}}^{2}}}{{{\cancel{x}}^{4}}-{{\cancel{y}}^{4}}}}{{{x}^{2}}-{{y}^{2}}}=1:({{x}^{2}}-{{y}^{2}})\]
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