A) 100%
B) 25.20%
C) 40.2%
D) 81.2%
Correct Answer: D
Solution :
For full wave rectifier \[\eta =\frac{81.2}{1+\frac{{{r}_{f}}}{{{R}_{L}}}}\] Þ \[{{n}_{\max }}=81.2%\] (rf << RL)
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