A) 1015 cm3
B) 1013 /cm3
C) 1012 /cm3
D) 1016 /cm3
Correct Answer: D
Solution :
\[\sigma =e{{n}_{e}}{{\mu }_{e}}\] Þ\[{{n}_{e}}=\frac{\sigma }{e{{\mu }_{e}}}=\frac{6.24}{1.6\times {{10}^{-19\times 3900}}}={{10}^{16}}/c{{m}^{3}}\]You need to login to perform this action.
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