8th Class Mathematics Related to Competitive Exam Question Bank Series

  • question_answer
    3, 4, 5, 5, 12, 13, 7, 24, 25, 9, 41?

    A) 16                               

    B) 24

    C) 35                               

    D) 40

    Correct Answer: D

    Solution :

    Numbers are in sets of three such that each set forms a Pythagorean triple, i.e, \[{{3}^{2}}+{{4}^{2}}={{5}^{2}},{{5}^{2}}+{{12}^{2}}={{13}^{2}},{{7}^{2}}+{{24}^{2}}={{25}^{2}}\]and so on. Quicker: 2nd number m each set is (1st number \[\times n+n\]) Method: Where, n= 1,2,3........ is set no. next number in the series is \[(9\times 4+4)=40\]


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