A) \[A=B=C\]
B) \[A\subseteq B=C\]
C) \[A=B\subseteq C\]
D) \[A\subseteq B\subseteq C\]
Correct Answer: D
Solution :
[d] \[\because \]\[A\cup B=B\cap C\] From above, strong inference is \[A\subseteq B\subseteq C\] e.g. \[A=\{a\},\]\[B=\{a,b\},\]\[C=\{a,b,c\}\] \[\therefore \] \[A\cup B=\{a,b\}\] and \[B\cap C=\{a,\,b\}\] |
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