A) \[A'\cup B'\cap C'\]
B) \[A'\cap B'\cap C'\]
C) \[A'\cap B'\cup C'\]
D) \[A\cap B\cap C\]
Correct Answer: C
Solution :
[c] We know that, \[[(A\cup B)\cap C]'=(A\cup B)'\cup C'\] \[=(A'\cap B')\cup C'\] \[=A'\cap B'\cup C'\] [by De-Morgan's law] |
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