A) 2
B) 4
C) 8
D) 12
Correct Answer: C
Solution :
| [c] Given set is \[\{(a,b):2{{a}^{2}}+3{{b}^{2}}=35;a,b\in Z\}\] We can see that, \[2\,{{(\pm \,2)}^{2}}+3\,{{(\pm \,3)}^{2}}=35\] and \[2\,{{(\pm \,4)}^{2}}+3{{(\pm \,1)}^{2}}=35\] \[\therefore \] \[(2,\,3),\]\[(2,\,-3),\]\[(-\,\,2,-3),\]\[(-\,\,2,3),\]\[(4,1),\] \[(4,-\,1),\]\[(-\,\,4,-1),\]\[(-\,\,4,1)\]are \[8\] elements of the set. \[\therefore \] \[n=8\] |
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