A) \[A\cup P(A)=P(A)\]
B) \[A\cup P(A)=A\]
C) \[A-P\,(A)=A\]
D) \[P\,(A)-\{A\}=P(A)\]
Correct Answer: C
Solution :
[c] \[A-P(A)=A'\] which is correct as A and P [A] are disjoint sets. |
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