A) A
B) B
C) \[\varphi \]
D) \[A\cap {{B}^{c}}\]
Correct Answer: D
Solution :
\[A\cap {{(A\cap B)}^{c}}=A\cap ({{A}^{c}}\cup {{B}^{c}})\] = \[(A\cap {{A}^{c}})\cup (A\cap {{B}^{c}})\] = \[\varphi \cup (A\cap {{B}^{c}})=A\cap {{B}^{c}}\].You need to login to perform this action.
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