A) Rs. 40000
B) Rs. 36000
C) Rs. 32000
D) Rs. 28000
Correct Answer: C
Solution :
[c] Compound interest at 10% in \[1\frac{1}{2}yr\] compounded half-yearly \[=P\left[ {{\left( 1+\frac{10}{200} \right)}^{3}}-1 \right]=0.157625\,P\] And simple interest \[=\frac{P\times 10\times 3}{100\times 2}\] = 0.15 P According to the question, 0.157625 \[P-0.15\,P=244\] \[\Rightarrow \] 0.007625 P= 244 \[\Rightarrow \] \[P=\text{Rs}.\,32000\] |
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