A) 57960
B) 42840
C) 44820
D) 50400
Correct Answer: B
Solution :
[b] \[\because \]P = 45000, \[{{r}_{1}}=12%,\] \[{{r}_{2}}=-15%\] \[\therefore \] \[A=P\left( 1+\frac{{{r}_{1}}}{100} \right)\left( 1+\frac{{{r}_{2}}}{100} \right)\] \[=45000\left( 1+\frac{12}{100} \right)\,\left( 1-\frac{15}{100} \right)=42840\] |
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