A) Rs. 6651
B) Rs. 6615
C) Rs. 6516
D) Rs. 6156
Correct Answer: B
Solution :
[b] Let each instalment = Rs. x \[\therefore \] \[x\left( \frac{100}{100+r} \right)+x{{\left( \frac{100}{100+r} \right)}^{2}}=A\] \[\Rightarrow \] \[x\left( \frac{100}{105} \right)+x{{\left( \frac{100}{105} \right)}^{2}}=12300\] \[x=\frac{12300\times 21\times 21}{20\times 41}=\text{Rs}.\,\,6615\] |
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