A) \[\frac{1}{3}\]
B) \[\frac{2}{3}\]
C) \[\frac{3}{5}\]
D) \[\frac{8}{3}\]
Correct Answer: A
Solution :
We have, \[\frac{6x-2}{9}+\frac{3x+5}{18}=\frac{1}{3}\] \[\Rightarrow \] \[\frac{2(6x-2)+(3x+5)}{18}=\frac{1}{3}\] \[\Rightarrow \] \[\frac{12x-4+3x+5}{18}=\frac{1}{3}\Rightarrow \frac{15x+1}{18}=\frac{1}{3}\] \[\Rightarrow \] \[45x+3=18\Rightarrow 45x=15\] \[\Rightarrow \] \[x=\frac{15}{45}=\frac{1}{3}\]You need to login to perform this action.
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