Step 1: Let the unit's digit be x |
Step 2: Then, ten's digit \[=(9-x)\] \[\therefore \] Number \[=10\times (9-x)+x\] \[\Rightarrow \] \[90-10x+x=(90-9x)\] |
Step 3: Adding 27 to the number \[90-9x,\] we get \[117-9x~\] |
Step 4: Number with digits interchanged is \[10x+(9-x)=9x+9\] |
Step 5: \[117-9x=9x+9\] |
Step 6: Therefore unit's digit = 6 and ten's digit = 3 |
Step 7: Hence the number = 36. |
A) Only Step 4
B) Both Step 1 and Step 2
C) Step 1, 2, 3 and 4
D) All steps are correct
Correct Answer: D
You need to login to perform this action.
You will be redirected in
3 sec